40x^2=490

Solution for 40x^2=490 equation:

40x^2=490

We move all terms to the left:

40x^2-(490)=0

a = 40; b = 0; c = -490;
Δ = b2-4ac
Δ = 02-4·40·(-490)
Δ = 78400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{78400}=280$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-280}{2*40}=\frac{-280}{80}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+280}{2*40}=\frac{280}{80}
=3+1/2
$